Question

VA ROG AJUTATI MA DAU COROANA!!!! doar a si b va rog eu nu scrieti prostii ca am nevoie urgenta!!!!​

Answer 1

Sper că te-am ajutat! Mult noroc la școală!

Answer 2

Explicație pas cu pas:

$\bf a) \: \: \dfrac{5}{7} \cdot \bigg( \dfrac{3 \cdot5 + 1}{5} + \dfrac{17}{10} \bigg) =$

$\bf \dfrac{5}{7} \cdot \bigg( \dfrac{16}{5} + \dfrac{17}{10} \bigg) =$

$\bf \dfrac{5}{7} \cdot \dfrac{16}{5} + \dfrac{5}{7} \cdot \dfrac{17}{10} =$

$\bf \dfrac{ \not5}{7} \cdot \dfrac{16}{ \not5} + \dfrac{ \not5}{7} \cdot \dfrac{17}{ \not10} =$

$\bf \dfrac{16}{ 7} + \dfrac{ 17}{14} =$

$\bf \dfrac{2 \cdot16}{ 14} + \dfrac{ 17}{14} =$

$\bf \dfrac{32 + 17}{ 14} =$

$\bf \dfrac{49}{ 14} = \dfrac{ \not49}{ \not14} =$

$\large\boxed{ \boxed{\bf \dfrac{7}{ 2}}}$

$\it~~~$

$\bf b) \: \: \dfrac{2}{5} \cdot \bigg( \dfrac{2 \cdot4 + 3}{4} - \dfrac{13}{12} \bigg) =$

$\bf \dfrac{2}{5} \cdot \bigg( \dfrac{11}{4} - \dfrac{13}{12} \bigg) =$

$\bf \dfrac{2}{5} \cdot \dfrac{11}{4} - \dfrac{2}{5} \cdot\dfrac{13}{12} =$

$\bf \dfrac{ \not2}{5} \cdot \dfrac{11}{\not4} - \dfrac{\not2}{5} \cdot\dfrac{13}{\not12} =$

$\bf \dfrac{ 1}{5} \cdot \dfrac{11}{2} - \dfrac{1}{5} \cdot\dfrac{13}{6} =$

$\bf \dfrac{ 11}{10} - \dfrac{13}{30}=$

$\bf \dfrac{ 3 \cdot 11}{30} - \dfrac{13}{30}=$

$\bf \dfrac{ 33 - 13}{30} =$

$\bf \dfrac{ 20}{30} = \dfrac{ \not20}{ \not30} =$

$\large \boxed{ \boxed{\bf \dfrac{ 2}{3}}}$

==pav38==