Question

Va rog ajutați-mă dau coruana !

Answer 1

{ x; y; z} dp { 3; 4; 6} => $\frac{x}{3} =\frac{y}{4} =\frac{z}{6} =k$=> x=3k; y=4k; z=6k

a)

z - y + x = 10

6k - 4k +3k =10

2k +3k =10

5k=10=> k=2. => x=6; y=8; z=12

b)

x+y-z=4

3k+4k-6k=4

7k-6k=4

k=4=> x=12; y=16; z=24

c)

y+z-x=21

4k+6k-3k=21

10k-3k=21

7k=21

k=3=> x=9; y=12; z=18