Question

Vă rog ajutați-mă,este urgent!Dau coroană!​

Answer 1

Ex. 1 a)$x^{2}$+2*x*2+$2^{2}$ = $x^{2}$+4x+4

b)$(3a)^{2}$+2*3a*4+$4^{2}$ = $9a^{2}$+24a+16

c)$x^{2}$-2*x*4+$4^{2}$ = $x^{2}$-8x+16

d)$(2x)^{2}$-2*2x*3y+$(3y)^{2}$ = $4x^{2}$-12xy+$9y^{2}$

e)$\sqrt{5} ^{2}$+2*$\sqrt{5}$*1+1 = 5+2$\sqrt{5}$+1 = 6+2$\sqrt{5}$

f)$3^{2}$+2*3*$\sqrt{3}$+$\sqrt{3} ^{2}$ = 9+6$\sqrt{3}$+3 = 12+6$\sqrt{3}$

g)$\sqrt{3}^{2}$-2*$\sqrt{3}$*2+$2^{2}$ = 3-4$\sqrt{3}$+4 = 7-4$\sqrt{3}$

h)$\sqrt{7}^{2}$-2*$\sqrt{7}$*$\sqrt{3}$+$\sqrt{3} ^{2}$ = 7-2$\sqrt{21}$+3 = 10-2$\sqrt{21}$

i)$x^{2}$-$3^{2}$ = $x^{2}$-9

j)$(5x)^{2}$-1 = 25$x^{2}$-1

k)$(x^{2}) ^2$-$\sqrt{7}^{2} }$=$x^{4}$-7

l)$(2x)^{2}$-$(3y)^{2}$=$4x^{2}$-$9y^{2}$

Ex.2

a)$x^{2}$+2*x*3+$3^{2}$+$x^{2}$-2*x*3+$3^{2}$-($x^{2}$-1)=2$x^{2}$+18-$x^{2}$+1 = $x^{2}$+19

b)$x^{2}$-2*x*5+$5^{2}$-($x^{2}$-$4^{2}$)+$x^{2}$+2*x*1+1=$x^{2}$-10x+25-$x^{2}$+16+$x^{2}$+2x+1=$x^{2}$-8x+32

c)$\sqrt{6} ^2$-2*$\sqrt{6}$*2+$2^{2}$+2(1+2*1*$\sqrt{6}$+$\sqrt{6} ^2$)+$\sqrt{6} ^2$-$\sqrt{2} ^2$ = 6-4$\sqrt{6}$+4+2+4$\sqrt{6}$+12+6-2=

= 28

Mult succes !