Question

VA ROG AJUTATI-MA!!!!!!!!!!
REPEDEEEEE!!!!
DAU COROANA!
ce cantitate de NaOH se obtine din 10 grame Na cu 8% impuritati in reactie cu apa?

Answer 1

2Na+2H2O=2NaOH+H2

$M_{Na}=23$

$M_{NaOH}=23+16+1=40$

Calculam masa pura de Na:

% Na pur= 100%-8%= 92%

$m= \dfrac{10*92}{100} =9,2 \ g \ Na$

Aplicam regula de 3 simpla:

46 g Na......80 g NaOH
9,2 g Na..........x

$x= \dfrac{80*9,2}{46}= 16\ g\ NaOH$