Question

va rog ajutati má un corp din aluminiu (densitatea2.7g/cm cub are volumul0.04 m cub sa se afle cit cintareste corpul va rog ajutati ma ​

Answer 1

$ro = \frac{2.7g}{ {cm}^{3} } = \frac{2.7 \times {10}^{ - 3} kg}{ {10}^{ - 6} {m}^{3} }$

$ro = \frac{m}{v} = > m = ro \times v = \frac{2.7 \times {10}^{ - 3} kg}{ {10}^{ - 6} {m}^{3} } \times 4 \times{10}^{ - 2} = \frac{2.7 \times {10}^{ - 3} kg}{ {10}^{ 3} {m}^{3} } \times 4 = 2.7 \times 4 × 10^{-1} = 1,08kg$