Question

va rog ajutatima:a)$\sqrt{3} (1-x \sqrt{2} )=3x \sqrt{6}$
b)$1-2(x+1)=3x+1$
macar explicatimi cum sa trec necunoscutele la stinga

Answer 1

√3(1-x√2)=3x√6
√3-x√6=3x√6
√3=3x√6+x√6
√3=4x√6
x=√3/4√6
x=√3*√6/4*6
x=√18/24
x=3√2/24
x=√2/8

1-2(x+1)=3x+1
1-2x-2=3x+1
1-2=3x+1+2x
5x+1=-1
5x=-1-1
5x=-2
x=-2/5