Question

Va rog ajutatima acum! a) [840-(1000-64x5):4]:10+33=
b) {12+3x[20-2x(7-10:5)]+13}x10=
c) [50+60x(7-3x2)]:10=
d)2x{42-[12+(8+2x5)]}=
e) [(38+8)x9+43x2]:100=
f) [(248:8-1x1):10]+(500:50+800:20)=

Answer 1

a) [840-(1000-64x5):4]:10+33=
= [840-(1000-320):4]:10+33=
= (840-680):4):10+33=
= (160:4):10+33=
= 40:10+33=
=4+33=37

b) {12+3x[20-2x(7-10:5)]+13}x10=
={12+3x[20-2x(7-2)]+13}x10=
=[12+3x(20-2x5)+13]x10=
=(12+3x10+13)x10=
=(12+30+13)x10=
=55x10=550

c) [50+60x(7-3x2)]:10=
=[50+60x(7-6)]:10=
=(50+60):10=
=110:10=11

d)2x{42-[12+(8+2x5)]}=
=2x{42-[12+(8+10)]}=
=2x[42-(12+18)]=
=2x(42-30)=
=2x12=24

e) [(38+8)x9+43x2]:100=
= (46x9+86):100=
= (414+86):100=
=500:100=5

f) [(248:8-1x1):10]+(500:50+800:20)=
 =[(31-1):10]+(10+40)=
 =30:10+50=
 =3+50=53