Question

vă rog ajutatima cu un raspuns​

Answer 1

Bună!

$\frac{3}{10} +\frac{3x-2}{4 } =1\frac{3}{10} -\frac{2x-4}{5} <=>$

$<=> \frac{3x-2}{4} +\frac{2x-4}{5}=\frac{13}{10}-\frac{3}{10} <=>$

$<=> ^{5)} \frac{3x-2}{4} +^{4)} \frac{2x-4}{5} =1 /*20 <=>$

$<=> 15x-10+8x-16=20 <=>$

$<=> 23x=20+26 => 23x=46 => x=2$

→$1\frac{3}{10} =\frac{1*10+3}{10} =\frac{13}{10}$

Answer 2

3/10+(3x-2)/4=1 3/10-(2x-4)/5

3/10+(3x-2)/4=13/10-(2x-4)/5

6/20+5(3x-2)/20=26/20-4(2x-4)/20

6+5(3x-2)=26-4(2x-4)

6+15x-10=26-8x+16

15x-4= -8x+42

15x+8x=42+4

23x=46

x=46:23

x=2