Question

va rog ajutatima ..rezolvati ecuatiile in multirea numerelor naturale 2x+3=8, 3x-5=4, 2x+2+3x+5=8,x+5=4, 4.x=6,2x+1=x

Answer 1

2x+3=8
8-3=5
x=5:2=2,5

3x-5=4
5+4=9
×=9:3=3

2x+2+3x+5=8
8-7=1
x=1:5=0,2

x+5=4
4-5=-1
×=-1

4×x=6
x=6:4=1,25

2x+1=x <= contradictie, deci nu se poate

Answer 2

$2x+3=8=\ \textgreater \ 2x=5=\ \textgreater \ x= \frac{5}{2}=2,5$
$3x-5=4=\ \textgreater \ 3x=9=\ \textgreater \ x=3$
$2x+2+3x+5=8=\ \textgreater \ 5x+7=8=\ \textgreater \ 5x=1=\ \textgreater \ x= \frac{1}{5}$
$4x=6=\ \textgreater \ x= \frac{6}{4} =1,5$
$2x+1=x=\ \textgreater \ 3x=1=\ \textgreater \ x= \frac{1}{3}$
$x+5=4=\ \textgreater \ x=-1$