Question

Va rog ajutor am nevoie urgentă ​

Answer 1

Răspuns:

a)2x+9《13 |-9

2x《4 |:2

x《2 => x€ (-infinit;2]

b)3x+4》16 |-4

3x》12 |:3

x》4 => x€[4;+infinit)

c)4x-2<10 |+2

4x<12 |:4

x<3 => x€(-infinit;3)

d)22-5x>7 |-22

-5x>-15 |×(-1)

5x<15 |:5

x<3 => x€(-infinit;3)

e)21-6x<9 |-21

-6x<-12 |×(-1)

6x>12 |:6

x>2 => x€(2;+infinit)

f)27-8x》3 |-27

-8x》-24 |×(-1)

8x《24 |:8

x《3 => x€(-infinit;3].

《= mai mic sau egal

》=mai mare sau egal