Question

va rog ajutor dau de toate!​ (Macar la punctul f sau g) dau si follpw

Answer 1

Răspuns:

Explicație pas cu pas:

e) 10·{24²:576+3·[(3²·2)¹⁵:(3²⁹·2¹⁵)+1²¹]}:13= 10·{1+3·[(3³⁰·2¹⁵):(3²⁹·2¹⁵)+1]}:13=

10·{1+3·[3+1]}:13=10·(1+3·4):13=10·13:13=10

f) 2¹⁰⁰:[2⁵⁰·2⁴⁸+(2¹⁰·2¹⁵)⁵:2²⁷+(5⁷⁶:5⁷⁵-3)⁹⁰·2⁸+2⁹⁸]=

2¹⁰⁰:[2⁹⁸+(2²⁵)⁵:2²⁷+(5-3)⁹⁰·2⁸+2⁹⁸]=2¹⁰⁰:[2⁹⁸+2¹²⁵:2²⁷+2⁹⁰·2⁸+2⁹⁸]=

2¹⁰⁰:(2⁹⁸+2⁹⁸+2⁹⁸+2⁹⁸)=2¹⁰⁰:2⁹⁸(1+1+1+1)=2¹⁰⁰:2⁹⁸·4=2¹⁰⁰:2⁹⁸·2²=2¹⁰⁰:2¹⁰⁰=1

g) [3⁷·3¹⁰+2²⁰³:2¹⁰⁸-5·(5²)⁵]:(3¹⁷+2⁹⁵-5¹¹)=(3¹⁷+2⁹⁵-5¹¹):(3¹⁷+2⁹⁵-5¹¹)=1

                             

Answer 2

Răspuns:

Explicație pas cu pas:

e)

= 10*{576:576+3*[(3³⁰*2¹⁵):(3²⁹*2¹⁵)+1]}:13

= 10*[ 1+3*( 3³⁰:3²⁹)*(2¹⁵:2¹⁵)+1] :13

= 10*( 1+3*(3*1+1):13

= 10*(1+3*4):13

= 10*13:13

= 10

-

f)

=2¹⁰⁰:[2⁹⁸+(2²⁵)⁵:2²⁷+(5-3)⁹⁰*2⁸+2⁹⁸]

=2¹⁰⁰:( 2⁹⁸+2¹²⁵:2²⁷+2⁹⁰*2⁸+2⁹⁸)

=2¹⁰⁰:( 2⁹⁸+2⁹⁸+2⁹⁸+2⁹⁸)

= 2¹⁰⁰:2⁹⁸*(1+1+1+1)

=2¹⁰⁰:2⁹⁸*4

=2¹⁰⁰:2⁹⁸*2²

=2¹⁰⁰:2¹⁰⁰

= 1

-

g)

=(3¹⁷+2⁹⁵-5*5¹⁰):(3¹⁷+2⁹⁵-5¹¹)

= (3¹⁷+2⁹⁵-5¹¹):(3¹⁷+2⁹⁵-5¹¹)

= doua paranteze egale se impart

= 1