Question

va rog am nevoie de ajutor cat de repede posibil​

Answer 1

Răspuns:

23.Fie c lungimea unei catete=. >si cealalta cateta are lungimea c

Aplici Pitagora

c²+c²=(8√3)²

2c²=64*3║:2

c²=32*3

c=√32*3

c=√16*2*3

c=4√6

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24.

cos <B=AB/BC

0,8=AB/10=>

AB=0,8*10

AB=8cm

Aplici pitagora si aflii AC

BC²=AB²+Ac²

10²=8²+AC²

100=64+AC²

AC=√(100-64)

AC=√36

AC=6

TGC=AB/AC=8/6=4/3

Explicație pas cu pas:

Answer 2

23.

$\it (c,\ c,\ c\sqrt2) - model\ pentru\ \Delta \ dreptunghic\ isoscel.\\ \\ c\sqrt2=8\sqrt3=4\cdot2\cdot\sqrt3=4\sqrt2\cdot\sqrt2\cdot\sqrt3=4\sqrt6\cdot\sqrt2 \Rightarrow c=4\sqrt6\ cm$

24.

$\it cosB=0,8 \Rightarrow \dfrac{AB}{BC}=0,8 \Rightarrow \dfrac{AB}{10}=\dfrac{8}{10} \Rightarrow AB=8\ cm\\ \\ (6,\ 8,\ 10)\ -\ triplet\ \ pitagoreic\ \Rightarrow AC=6\ cm\\ \\ tgC=\dfrac{AB}{AC}=\dfrac{\ \ 8^{(2}}{6}=\dfrac{4}{3}.$