Matematică, întrebare adresată de Utilizator anonim, 9 ani în urmă

VA ROG DAU 15 PUNCTE !!!calculati :a)  \frac{5}{12} + \frac{3}{20} + \frac{4}{15}
b) \frac{11}{20} + \frac{7}{10} + \frac{5}{16} [tex]
c) \frac{16}{21} + \frac{3}{28} + \frac{1}{42} [/tex]
d) \frac{8}{15} + \frac{11}{18} + \frac{4}{45}
e) \frac{17}{32} + \frac{1}{24} + \frac{7}{12}

Răspunsuri la întrebare

Răspuns de AndraI
0
a)  \frac{5}{12}+ \frac{3}{20}+ \frac{4}{15} =     \frac{5*5+3*3+4*4}{60} = \frac{25+9+16}{60}= \frac{50}{60}= \frac{5}{6}
b)  \frac{11}{20}+ \frac{7}{10} + \frac{5}{16}= \frac{4*11+8*7+5*5}{80}= \frac{44+56+25}{80}=  \frac{125}{80} =1 \frac{45}{80}
c)  \frac{16}{21} +  \frac{3}{28}+ \frac{1}{42}= \frac{4*16+3*3+1*2}{84}= \frac{64+9+2}{84}= \frac{75}{84}/3 = \frac{25}{28}
d)  \frac{8}{15} + \frac{11}{18} + \frac{4}{45}= \frac{6*8+11*5+4*2}{90}  = \frac{48+55+8}{90}=  \frac{111}{90} /3= \frac{37}{30}= 1\frac{7}{30}
e)  \frac{17}{32}+ \frac{1}{24}+ \frac{7}{12}=   \frac{3*17+1*4+8*7}{96}= \frac{51+4+56}{96}= \frac{111}{96} /3=  \frac{37}{32} = 1\frac{5}{32}
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