Question

VA ROG! DAU COROANA!!!!!

Answer 1

$\frac{a}{\sqrt{2}} =\frac{\sqrt{8}}{b}=>ab=\sqrt{2\times8} =\sqrt{16} =4$

$\frac{\sqrt{3c} }{\sqrt{15} } =\frac{1}{\sqrt{15d}} =>\sqrt{45cd} =\sqrt{15} ()^2=>45cd=15=> cd=\frac{15}{45}=\frac{1}{3}$

$=> ab-cd=4 - \frac{1}{3} =\frac{12}{3}-\frac{1}{3} =\frac{11}{3}$