Question

Va rog!!!!!! Dau coroana​

Answer 1

$2a)~\sqrt{10}=\sqrt{2}\cdot\sqrt{5}~~~~~~~~~~~~~~~~~~~~~~~~e)~\sqrt{45}= \sqrt{5}\cdot\sqrt{9} \\\\b)~\sqrt{15} =\sqrt{3}\cdot \sqrt{5} ~~~~~~~~~~~~~~~~~~~~~~~~~~f)~\sqrt{80}=\sqrt{8}\cdot \sqrt{10} \\\\c)~\sqrt{6}=\sqrt{2}\cdot\sqrt{3}~~~~~~~~~~~~~~~~~~~~~~~~~~~~g)~\sqrt{150}=\sqrt{10}\cdot \sqrt{15} \\\\d)~\sqrt{24}=\sqrt{4}\cdot\sqrt{6} ~~~~~~~~~~~~~~~~~~~~~~~~~~~h)~\sqrt{480} =\sqrt{10}\cdot \sqrt{48} \\\\~~~~~~~~~~~~~~~~~~~~~~~i)~\sqrt{845}=\sqrt{5}\cdot \sqrt{169}$

$3a)~\dfrac{\sqrt{27} }{\sqrt{3 } } =\sqrt{\dfrac{27}{3} }=\sqrt{9}=3 ~~~~~~~~~~~~~~~~~~~d)~\dfrac{\sqrt{216} }{\sqrt{6} }=\sqrt{\dfrac{216}{6} }=\sqrt{36}=6 \\\\\\b)~\dfrac{\sqrt{18} }{\sqrt{2} }=\sqrt{\dfrac{18}{2} } =\sqrt{9} =3~~~~~~~~~~~~~~~~~~~~~e)~\dfrac{\sqrt{512} }{\sqrt{8} }=\sqrt{\dfrac{512}{8} }=\sqrt{64}=8 \\\\\\c)~\dfrac{\sqrt{100} }{\sqrt{4} } =\sqrt{\dfrac{100}{4} } =\sqrt{25}=5~~~~~~~~~~~~~~~~f)~\dfrac{\sqrt{1728} }{\sqrt{12} } =\sqrt{\dfrac{1728}{12} }= \sqrt{144}= 12$

$4a)~\sqrt{45}:\sqrt{5}=\sqrt{45:5}=\sqrt{9}=3 ~~~~~~d)~\sqrt{150}:\sqrt{6}=\sqrt{150:6}=\sqrt{25}=5 \\\\b)~\sqrt{27}:\sqrt{3} =\sqrt{27:3}= \sqrt{9}=3~~~~~~~~e)~\sqrt{448}:\sqrt{7}=\sqrt{448:7}= \sqrt{64} =8\\\\c)~\sqrt{72}:\sqrt{8}=\sqrt{72:8}=\sqrt{9}=3 ~~~~~~~~f)~\sqrt{972}:\sqrt{12}=\sqrt{972:12}= \sqrt{81}=9$

$5a)~\dfrac{\sqrt{60}-\sqrt{65} }{\sqrt{5} }=\dfrac{\sqrt{60} }{\sqrt{5} } -\dfrac{\sqrt{65} }{\sqrt{5} } =\sqrt{\dfrac{60}{5} }-\sqrt{\dfrac{65}{5} } =\sqrt{12}- \sqrt{13} \\\\\\b)~\dfrac{\sqrt{48}+\sqrt{12} }{\sqrt{3} } =\dfrac{\sqrt{48} }{\sqrt{3} }-\dfrac{\sqrt{12} }{\sqrt{3} }=\sqrt{\dfrac{48}{3} }-\sqrt{\dfrac{12}{3} }=\sqrt{16}-\sqrt{4}=4-2=2$

$c)~\dfrac{\sqrt{18} -\sqrt{6} }{\sqrt{2} }=\dfrac{\sqrt{18} }{\sqrt{2} }-\dfrac{\sqrt{6} }{\sqrt{2} }=\sqrt{\dfrac{18}{2} }-\sqrt{\dfrac{6}{2} } =\sqrt{9}-\sqrt{3}=3-\sqrt{3} \\\\\\d)~\dfrac{\sqrt{99} +\sqrt{44} }{\sqrt{11} }=\dfrac{\sqrt{99} }{\sqrt{11} }+\dfrac{\sqrt{44} }{\sqrt{11} }=\sqrt{\dfrac{99}{11} }+\sqrt{\dfrac{44}{11} }=\sqrt{9}+\sqrt{4}=3+2=5$