Question

va rog dau coroana.Doar c) de la fiecare ex!!!​

Answer 1

Explicație pas cu pas:

scrise sub formă de putere:

$\bigg(\dfrac{2}{5}\bigg)^{6} \cdot \bigg(\dfrac{2}{5}\bigg)^{19} = \bigg(\dfrac{2}{5}\bigg)^{6+19} = \bigg(\dfrac{2}{5}\bigg)^{25}$

$\bigg(\dfrac{4}{3}\bigg)^{35} : \bigg(\dfrac{4}{3}\bigg)^{21} = \bigg(\dfrac{4}{3}\bigg)^{35 - 21} = \bigg(\dfrac{4}{3}\bigg)^{14}$

$\bigg[\bigg(\dfrac{3}{4}\bigg)^{11}\bigg]^{4} = \bigg(\dfrac{3}{4}\bigg)^{11 \cdot 4} = \bigg(\dfrac{3}{4}\bigg)^{44}$

Answer 2

(2/5)^6 • (2/5)^19= (2/5)^6+19= (2/5)^25
(4/3)^35 : (4/3)^21= (4/3)^35-21=(4/3)^14
[(4/3)^11]4=(3/4)^44

Sper ca te am ajutat!