Question

Vă rog dau coroana e pe maine

Answer 1

h)7^2×(27^3÷9^4+1)
=49(27^3 pe 9^4 +1)
=49((3^3)^3 pe (3^2)^4 +1)
=49(3^9 pe 3^8 +1)
=49(3+1)=49×4
=196

i)74÷(2017^2017 +2017^0 +0^2017)^0
=74÷1=74

j)4×(23+5(23-4×2^2))+2017^0
=4(23+5(23-4×4))+1
=4(23+5(23-16))+1
=4(23+5×7)+1
=4×58+1=232+1
=233

k)2^0+5(5^100 +5^99 +5^98)÷5^98+343÷7^2
=1+5(5^2+5+1)×5^98÷5^98+343 pe 7^2
=1+5(25+5+1)×5^98÷5^98+343 pe 49
=1+5×31×5^98÷5^98+7
=1+5×31×1+7=1+155+7
=163

l)9+8×(76-5×(4+3×(3^2-2^3)))
=9+8(76-5(4+3(9-8)))
=9+8(76-5(4+3×1))
=9+8(76-5(4+3))
=9+8(76-5×7)
=9+8×41=9+328
=337