Question

va rog din suflet ajutati.ma urgent cu acest exercitiu​

Answer 1

Răspuns:

$\frac{x+2)2x+1}{x-2} +\frac{x-2)1-2x}{x+2} +\frac{x^{2} +16}{x^{2}-4} =$

$=\frac{2x^{2}+5x+2+x-2x^{2}-2+4x+x^{2}+16}{(x+2)(x-2)}=$$=\frac{x^{2}+10x+16}{(x+2)(x-2)}=\frac{x^{2}+4x+4+6x+12}{(x+2)(x-2)}=\frac{(x+2)^{2}+6(x+2)}{(x+2)(x-2)}=$

$=\frac{(x+2)(x+7)}{(x+2)(x-2)}=\frac{x+7}{x-2}$

Explicație pas cu pas: