Question

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Answer 1

$\it \dfrac{^{3)}3}{4}+ \dfrac{^{4)}5}{3}=\dfrac{9+20}{12}=\dfrac{29}{12}=2\dfrac{5}{12}\\ \\ \\ \dfrac{^{11)}15}{7}+ \dfrac{^{7)}13}{11}=\dfrac{165+91}{77}=\dfrac{256}{77}= 3\dfrac{25}{77}$

$\it \dfrac{^{11)}3}{13}+ \dfrac{^{13)}1}{11}=\dfrac{33+13}{143}=\dfrac{46}{143}\\ \\ \\ \dfrac{^{7)}11}{5}+ \dfrac{^{5)}3}{7}=\dfrac{77+15}{35}=\dfrac{92}{35}$

$\it 1\dfrac{1}{7}+1\dfrac{2}{11}=2+\dfrac{^{11)}1}{7}+ \dfrac{^{7)}2}{11}=2+\dfrac{11+14}{77}=2+\dfrac{25}{77}=2\dfrac{25}{77}$

Answer 2

Răspuns:

a.3/4 + 5/3 = 3×3/4×3 + 5×4/3×4 = 9/12 + 20/12 = 29/12 .

b.15/7 + 13/11 = 15×11/7×11 + 13×7/11×7 = 165/77 + 91/77 = 256/77.

c.3/13 + 1/11 = 3×11/13×11 + 1×13/11×13 = 33/143 + 13/143 = 46/143.

d.16/3 + 11/37 =16×37/3×37 + 11×3/37×3 = 592/111 + 33/111 = 625/111.

e.11/5 + 3/7 = 11×7/5×7 + 3×5/7×5 = 77/35 + 15/35 = 92/35.

f.1/11 + 5/19 = 1×19/11×19 + 5×11/19×11 = 19/209 + 55/209 = 74/209.

g.3/5 + 1/23 = 3×23/5×23 + 1×5/23×5 = 69/115 + 5/115 = 74/115.

h.1 1/7 + 1 2/11 = (1+1) + (1/7 + 2/11) = 2 + 25/77 = 2 25/77