Question

Va rog e urgent îmi trebuie neaparat in seara asta dau coroanaaaa va roggggg metoda de clasa a 8 a vrggg

Answer 1

Răspuns:

Explicație pas cu pas:

a) x³+x²-x-1=x³-x+x²-1=x(x²-1)+x²-1=(x²-1)(x+1)=(x-1)(x+1)(x+1)=(x-1)(x+1)²

b) x⁶-x⁴-81x²+81=x⁶-81x²-x⁴+81=x⁴(x²-81)-(x⁴-81)=(x⁴-81)(x⁴-1)=

(x²+9)(x²-9)(x²+1)(x²-1)=(x²+9)(x-3)(x+3)(x²+1)(x+1)(x-1)

c) x⁵-x³-x²+1=x⁵-x²-x³+1=x²(x³-1)-(x³-1)=(x³-1)(x²-1)=(x³-1)(x+1)(x-1)

d) x³+x²-25x-25=x³-25x+x²-25=x(x²-25)-(x²-25)=(x²-25)(x-1)=(x+5)(x-5)(x-1)

e) x³-9x²-x+9=x²(x-9)-(x-9)=(x-9)(x²-1)=(x-9)(x+1)(x-1)

f) x³-4x²-16x-64=x³-16x+4x²-64=x(x²-16)+4(x²-16)=(x²-16)(x+4)=

(x+4)(x-4)(x+4)=(x+4)²(x-4)

g) 4x³-12x²-x+3=4x²(x-3)-(x-3)=(x-3)(4x²-1)=(x-3)(x+1)(x-1)

h) 9x³-18x²-4x+8=9x²(x-2)-4(x-2)=(x-2)(9x²-4)=(x-2)(3x-2)(3x+2)

i) 4x³-20x²-9x+45=4x²(x-5)-9(x-5)=(x-5)(4x²-9)=(x-5)(2x+3)(2x-3)

j) 9x³+27x²-4x-12=9x²(x+3)-4(x+3)=(x+3)(9x²-4)=(x+3)(3x+2)(3x-2)

k) 16x³+32x²-9x-18=16x²(x+2)-9(x+2)=(x+2)(16x²-9)=(x+2)(4x+3)(4x-3)

l) 25x³-50x²-4x+8=25x²(x-2)-4(x-2)=(x-2)(25x²-4)=(x-2)(5x-2)(5x+2)