Question

Va rog este urgent!!!!​

Answer 1

$a) \frac{1}{9} {x}^{2} y(9x - 3 {y}^{2})$

$= \frac{1}{9} {x}^{2} y(3x - {y}^{2} )$

$= \frac{1}{3} {x}^{2} y(3x - {y}^{2} )$

$= {x}^{3} y - \frac{1}{3} {x}^{2} y {}^{3}$

$b) \frac{2}{3} x {y}^{2} (2 {y}^{2} + 3 {x}^{2} )$

$= \frac{2}{3} x {y}^{2} \times 2 {y}^{2} + \frac{3}{3} x {y}^{2} \times 3 {x}^{2}$

$= \frac{4}{3} x {y}^{4} + 2x {y}^{2} {x}^{2}$

$= \frac{4}{3} xy {}^{4} + 2x {}^{3} {y}^{2}$