Question

VA ROG ESTE URGENT : DETERMINATI FORMULA MOLECULARA A SUBSTANTEI CU FORMULA PROCENTUALA 40% C 6.66 % H  SI 53.33 % o SI CARE ARE 2 ATOMI DE O IN MOLECULA!.MULTUMESC!

Answer 1

C : $\frac{40}{12}$ = 3,33
H : $\frac{6.66}{1}$ = 6,66
O : $\frac{53.33}{16}$ = 3,33
Impartim totul la 3,33
C: $\frac{3,33}{3,33.}$ = 1
H: $\frac{6.66}{3.33}$ = 2
O: $\frac{3,33}{3,33}$ = 1
Formula moleculara : CH2O
Deoarece are 2 atomi de O in molecula => Formula moleculara : C2H4O2