Question

Va rog ex 1 si 2 prin metoda mersului invers

Answer 1

Răspuns:

ex:1

10+10÷{[10+10×(x-10)]÷10-10}=11

10÷{[10+10×(x-10)]÷10-10}=11-10

10÷{[10+10×(x-10)]÷10-10}=1

10+10×(x-10)÷10-10=10÷1

10+10×(x-10)÷10-10=10

10+10×(x-10)÷10=10+10

10+10×(x-10)÷10=20

10×(x-10)÷10=20-10

10×(x-10)÷10=10

10×(x-10)=10×10

10×(x-10)=100

x-10=100:10

x-10=10

x=10+10

x=20(sper ca este corect)

EX.2

aici nu trebuie neaparat metida mersului invers si putem face:

3208-100=3108

dar daca vrei prin metoda mersului invers e asa

x+100=3208

x=3208-100

x=3108