Question

Va rog ex 10 dau coroana!!

Answer 1

$a) \sqrt{24} = \sqrt{2 \times 2 \times 2 \times 3} = \sqrt{(2 \times 2) \times 2 \times 3} = \sqrt{ {2}^{2} \times 2 \times 3 } = 2 \sqrt{2 \times 3} = 2 \sqrt{6}$

$b) \sqrt{63} = \sqrt{3 \times 3 \times 7} = \sqrt{(3 \times 3) \times 7} = \sqrt{ {3}^{2} \times 7 } = 3 \sqrt{7}$

$c) \sqrt{98} = \sqrt{2 \times 7 \times 7} = \sqrt{(7 \times 7) \times 2} = \sqrt{ {7}^{2} \times 2 } = 7 \sqrt{2}$

$d) \sqrt{96} = \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 3} = \sqrt{(2 \times 2) \times (2 \times 2) \times 2 \times 3} = \sqrt{ {2}^{2} \times {2}^{2} \times 2 \times 3 } = (2 \times 2) \sqrt{2 \times 3} = 4 \sqrt{6}$

$e) \sqrt{200} = \sqrt{2 \times 2 \times 2 \times 5 \times 5} = \sqrt{(2 \times 2) \times (5 \times 5) \times 2} = \sqrt{ {2}^{2} \times {5}^{2} \times 2 } = (2 \times 5) \sqrt{2} = 10 \sqrt{2}$

$f) \sqrt{108} = \sqrt{2 \times 2 \times 3 \times 3 \times 3} = \sqrt{(2 \times 2) \times (3 \times 3) \times 2} = \sqrt{ {2}^{2} \times {3}^{2} \times 2 } = (2 \times 3) \sqrt{3} = 6 \sqrt{3}$