Question

va rog ex 7 si minitestul !! va implor​

Answer 1

Răspuns:

7)25^18=(5^2)^18=5^36; 125^15=(5^3)^15=5^45

5^36, 5^40, 5^45 adica 25^18,5^40,125^15

9^51=(3^2)^51=3^102; 27^48=(3^3)48=3^144;

deci avem: 3^95; 9^51; 27^48

8^12=(2^3)^12=2^36; 32^7=(2^5)^7=2^35

27^8=(3^3)^8=3^24; 32^7, 8^12, 27^8

1)a) 2^51>2^18

b)7^32<9^32

2)25^ab=(5^2)^ab<5^26=> ab<26÷2, ab<13=>ab=12

3)4^32=(2^2)^32=2^64

8^24=(2^3)^24=2^72

16^25=(2^4)^25=2^100

2^64, 2^72, 2^100

4)???