Question

Va rog.
Ex. 8
DAU COROANĂ! + 45 PUNCTE

Answer 1

$\it \{a,b\}\ i. \ p.\ \{6,5\} \Rightarrow 6a = 5b \Rightarrow a = \dfrac{5}{6}b\ \ \ \ (*)\\ \\ \dfrac{4a-b}{2a+3b}\ \stackrel{(*)}{=}\ \dfrac{4\cdot\dfrac{5}{6}b-b}{2\cdot\dfrac{5}{6}b+3b}=\dfrac{\not{b}\left(\dfrac{10}{3}-1\right)}{\not{b}\left(\dfrac{5}{3}+3\right)}=\dfrac{\dfrac{7}{3}}{\dfrac{11}{3}} =\dfrac{7}{11}$