Question

vă rog foarte mult ajutor urgent ​

Answer 1

<C=180°-105°=75° => ΔABC isoscel => AB=BC=10

$A_{ΔABC}=\dfrac{AB×BC×\sin B}{2}\\\\ A_{ΔABC}=\dfrac{10×10×\sin 30^{\circ}}{2}\\\\ A_{ΔABC}=50×\dfrac{1}{2}=25\:\:cm^2$