Question

Va rog frumos.[3^2*3^3+2^54:2^52+(3^5)^4:3^20]:31= ?

[3^48:3^18+(2^4)^5+6^23:6^13] :[(3^5)^2*(2^2)^5+3^17*3^13+(2^5)^4]=?

Answer 1

$[3^2*3^3+2^{54}:2^{52}+(3^5)^4:3^{20}]:31= (3^5+2^2+3^{20}:3^{20}):31=(243+4+1):31= 248:31=8$

$[3^{48}:3^{18}+(2^4)^5+6^{23}:6^{13}] :[(3^5)^2*(2^2)^5+3^{17}*3^{13}+(2^5)^4]= (3^{30}+2^{20}+6^{10}) :(3^{10}*2^{10}+3^{30}+2^{20})= (3^{30}+2^{20}+6^{10}) :(6^{10}+3^{30}+2^{20})= 1$