Question

vă rog frumos 3,4vsi 5 până în ora 4:00

Answer 1

3.$a)\frac{8}{13}\cdot\frac{26}{11}+(-\frac{5}{11})=\frac{8\cdot2}{11}\cdot(\frac{-5}{11})=\frac{16-5}{11}=\frac{11}{11}=1$

$b)2,5\cdot(-4)+(-2)^{5}=-10-32=-42$

$c)(-1)^{23}\cdot(-4)+(-2)^{5}=-1+8\cdot\frac{1\cdot4+1}{4}=-1+8\cdot\frac{5}{4}=-1+2\cdot5=-1+10=9$

$d)\frac{2}{21}\cdot5\frac{1}{4}-3:\frac{6}{11}=\frac{2}{21}\cdot\frac{5\cdot4+1}{4}-3\cdot\frac{11}{6}=\frac{2}{21}\cdot\frac{21}{4}-\frac{11}{2}=\frac{2}{4}- \frac{11}{2}=\frac{1}{2}-\frac{11}{2}=-\frac{10}{2}=-5$

$e)\frac{7}{25}:(\frac{3}{5})^{2}+\frac{2}{6}:\frac{3}{11}=\frac{7}{9}+\frac{11}{9}=\frac{18}{9}=2$

$f)4,3\cdot2+5\cdot1,7-\frac{1}{10}=8,6+8,5-\frac{1}{10}=\frac{86}{10}+\frac{85}{10}-\frac{1}{10}=-\frac{70}{10}=17$

toate sunt numere intregi: 1, -42, 9, -5; 2 si 17

4.$(1-\frac{19}{20})\cdot(-5)+\frac{13}{4}=\frac{20-19}{20}-5+\frac{13}{4}=\frac{1}{20}-5-\frac{13}{4}=\frac{1-5\cdot20+13\cdot5}{20}=\frac{1-100+65}{20}=\frac{-34}{20}= -1,7$

$b)\frac{2}{7}-(1-\frac{5}{7})\cdot(\frac{13}{2}-\frac{3}{4})=\frac{2}{7}-(\frac{7-5}{7})\cdot(\frac{13\cdot2-3}{4})=\frac{2}{7}-\frac{2}{7}\cdot\frac{23}{4}=-\frac{38}{28}$

$c)2\cdot(\frac{5}{7}-\frac{1}{3})-(\frac{2}{7})^{2}\cdot\frac{14}{3}=$

$=2\cdot\frac{5\cdot3-7}{21}-\frac{4}{49}\cdot\frac{14}{3}=2\cdot\frac{15-7}{21}-\frac{8}{21}=\frac{4}{21}-\frac{8}{21}=-\frac{4}{21}$

$d)2[5-\frac{5}{8}(\frac{1}{3}-\frac{3}{5}=2\cdot[5-\frac{5}{8}(\frac{5-9}{15})]=2\cdot[5-\frac{5}{8}(\frac{-4}{15})]=2\cdot[5-\frac{-20}{120}]=2\cdot\frac{600+20}{120}=\frac{620}{60}=\frac{31}{3}$

$e)\frac{1}{4}:[\frac{5}{4}-\frac{2}{3}(1,5-0,75)]=\frac{1}{4}:(\frac{5}{4}-\frac{2}{3}\cdot0,75)=\frac{1}{4}:(\frac{5}{4}-\frac{2}{3}\cdot\frac{5}{4})=\frac{1}{4}: \frac{15-10}{12}=\frac{1}{4}:\frac{5}{12}=\frac{1}{4}\cdot\frac{12}{5}=\frac{3}{5}$

5.

$a)1-(-\frac{1}{2})^{2}+(-\frac{1}{2})^{3}-(-\frac{1}{2})^{4}=1-\frac{1}{4}-\frac{1}{8}- \frac{1}{16}=\frac{16-8-4-1}{16}=\frac{3}{16}$