Question

va rog frumos ajutatima​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Răspuns: $\bf \dfrac{15}{11}$

Explicație pas cu pas:

Salutare!

$\bf \dfrac{x}{y} = \dfrac{2}{3} \implies 3\cdot x = 2\cdot y \implies \boxed{\bf x =\dfrac{2y}{3} }$

$\bf \dfrac{6x+y}{x +3y}$  inlocuim pe x in aceasta relatie si vom avea:

$\bf \dfrac{6\cdot \dfrac{2y}{3} +y}{\dfrac{2y}{3} +3y} = \dfrac{\not6\cdot \dfrac{2y}{\not3} +y}{\dfrac{2y}{3} +\dfrac{3y}{1}}=\dfrac{2\cdot 2y+y}{\dfrac{2y}{3} +\dfrac{3\cdot 3y}{3}}=\dfrac{5y}{\dfrac{2y+9y}{3}}=\dfrac{5y}{\dfrac{11y}{3}}=$

$\bf \dfrac{5y}{1} :\dfrac{11y}{3}= \dfrac{5y}{1} \cdot\dfrac{3}{11y}=\dfrac{5\not y}{1} \cdot\dfrac{3}{11\not y}= \dfrac{5}{1} \cdot\dfrac{3}{11}=\boxed{\bf \dfrac{15}{11}}$

==pav38==