Question

Va rog frumos am nevoie

Answer 1

Răspuns:

Explicație pas cu pas:

• f(0)= f(0+0)=af(0)+af(0)+g(0+0)=2af(0)=g(0)= 2af(0)+0=2af(0)

f(0)=2af(0)⇒cu a≠0, f(0)=0

• f(0)=0 (punctul a)= f(x-x) =af(x) +af(-x)+g(x-x)=
• af(x) +af(-x)+g(0)=af(x) +af(-x)
• a(f(x) +f(-x))=0  cu a≠0, avem f(x) +f(-x)=0⇔f(-x) =-f(x), f(x) impara

f(x)=f(x+0)=af(x) +af(0)+g(x+0)=af(x)+g(x)

f(x) (1-a)=g(x)

f(x) =(1/(1-a)) *g(x)

obs ..probabil la date era a≠1, nu 2a≠1