Question

Va rog frumos cel tarziu luni sa-mi da-ti raspuns!
Diagonala unui patrat are lungimea de 12√2.Determinati perimetrul patratului
explicati cum ati facut

Answer 1

d=l√2
12√2=l√2
l√2=12√2
l=12√2/√2
l=12 cm
Perimetrul=4*l=4*12=48cm

Answer 2

$d=12\sqrt 2 \\ d^2=l^2+l^2 \\ 2l^2=12^2\sqrt 2^2 \\ 2l^2=144 \cdot 2 \\ 2l^2=288 \\ l^2=\frac{288}{2} \\ l^2=144 \\ l=\sqrt{144} \\ l=12 \\ P=4l \\ P=4 \cdot 12 \\ \boxed{P=48}$