Question

VA ROG FRUMOS CINE MA POATE AJUTA !
SUNT PE FILOLOGIE SI NU MA DESCURC CU MATEMATICA !!!

aranjamente de 11 luate cate 6 - aranjamente de 11 luate cate 5 /
aranjamente de 10 luate cate 5 - aranjamente de 10 luate cate 4

V A ROG FRUMOS ! ROG SERIOZITATE !

30 puncte si coroana

Answer 1

Răspuns:11

Explicație pas cu pas:

Answer 2

Răspuns:

Vezi, am o secventa de 2 ori.... Nu am reusit s-o sterg....

Explicație pas cu pas:

$\dfrac{A_{11}^{6}-A_{11}^{5}}{A_{10}^{5}-A_{10}^{4}} =???\\A_{11}^{6}-A_{11}^{5}=\dfrac{11!}{(11-6)!} -\dfrac{11!}{(11-5)!}=\dfrac{11!}{5!} -\dfrac{11!}{6!}=\dfrac{5!*6*7*8*9*10*11}{5!}-\dfrac{6!*7*8*9*10*11}{6!}=7*8*9*10*11*(6-1)=7*8*9*10*11*5\\A_{10}^{5}-A_{10}^{4}=\dfrac{10!}{(10-5)!} -\dfrac{10!}{(10-4)!}=\dfrac{10!}{5!} -\dfrac{10!}{6!}=\dfrac{5!*6*7*8*9*10}{5!}-\dfrac{6!*7*8*9*10}{6!}=7*8*9*10(6-1)=7*8*9*10*5$

$\dfrac{A_{11}^{6}-A_{11}^{5}}{A_{10}^{5}-A_{10}^{4}} =???\\A_{11}^{6}-A_{11}^{5}=\dfrac{11!}{(11-6)!} -\dfrac{11!}{(11-5)!}=\dfrac{11!}{5!} -\dfrac{11!}{6!}=\dfrac{5!*6*7*8*9*10*11}{5!}-\dfrac{6!*7*8*9*10*11}{6!}=7*8*9*10*11*(6-1)=7*8*9*10*11*5\\A_{10}^{5}-A_{10}^{4}=\dfrac{10!}{(10-5)!} -\dfrac{10!}{(10-4)!}=\dfrac{10!}{5!} -\dfrac{10!}{6!}=\dfrac{5!*6*7*8*9*10}{5!}-\dfrac{6!*7*8*9*10}{6!}=7*8*9*10(6-1)=7*8*9*10*5$

$Deci~~~\dfrac{A_{11}^{6}-A_{11}^{5}}{A_{10}^{5}-A_{10}^{4}} =\dfrac{7*8*9*10*11*5}{7*8*9*10*5} =11$