Question

Va rog frumos exercițiul 4! Mulțumesc anticipat!

Answer 1

$C_{4} ^{2}= \frac{4!}{2!*2!}= \frac{2!*3*4}{2!*2!}=6 \\ C_{4} ^{3}= \frac{4!}{3!}=4 \\ C_{5} ^{2}= \frac{5!}{2!*3!}= \frac{3!*4*5}{2!*3!}= 10 \\ P(A)= \frac{m}{n}= \frac{1}{3}$