Question

va rog frumos, ma poate ajuta cineva? ( 3×100-75) :5= ; 3×[(100-75) :5] =; 9+2 × [30-4 ×(8-6:2)]=; (2100-1965) : (3×3) :(25:5)×10 = ; 4×4 - {3×167-2×[3+4×(5+6×7)-8]}:9= ; 960:10 :2 :8 :3 = ; 124 +(368:8×9)- (128×3:4)= ; 124 +32 :8×115-81:9:3×100 =​ va rog frumos ma poate ajuta cineva ?​1​

Answer 1

(3x100-75):5=(300-75):5=225:5=45
3x[(100-75):5]=3x(25:5)=3x5=15