Question

va rog frumos! macar sa încercați, dau coroana

Answer 1

$\frac{\frac{128}{15}*(\frac{1}{5}+x*(\frac{4}{3}-\frac{6}{5}))*\frac{5}{3}}{\frac{192}{90}}=\frac{(2^{4})^{8}}{(2^3)^{10}}\\\\\frac{128}{15}*(\frac{1}{5}+x*(\frac{4}{3}-\frac{6}{5}))*\frac{5}{3}}=\frac{2^{32}}{2^{30}}*\frac{192}{90}=\frac{2^{2}*192}{90}=\frac{384}{45}\\\\\frac{128}{15}*(\frac{1}{5}+x*(\frac{4}{3}-\frac{6}{5}))=\frac{384}{45};\frac{5}{3}=\frac{384}{45}*\frac{3}{5}=\frac{1152}{225}$

$\frac{1}{5}+x*(\frac{4}{3}-\frac{6}{5})=\frac{1152}{225}:\frac{128}{15}=\frac{1152}{225}*\frac{15}{128}=\frac{9}{15}\\\\x*(\frac{4}{3}-\frac{6}{5})=\frac{9}{15}-\frac{1}{5}=\frac{9}{15}-\frac{3}{15}=\frac{6}{15}=\frac{2}{5}\\\\x*(\frac{20}{15}-\frac{18}{15})=x*\frac{2}{15}=\frac{2}{5}\\\\x=\frac{2}{5}:\frac{2}{15}=\frac{2}{5}*\frac{15}{2}=3$