Question

va rog frumos multumesc

Answer 1

1
a)4:0,01=400buc
b)4:0,05=80 buc
c)4:0,10=40 buc
d)4:0,50=8 buc

2
(2*5)+(20*0,50)=20
(1*10)+(10*0.50)+(50*0,10)=20
sunt mai multe combinatii
pb 3
a)9-3=6
b)9:3=3
c)(3*25)+(9*20)=75+180=255
d)(3*100)-255=300-255
=45