Matematică, întrebare adresată de Ale20099, 8 ani în urmă

Va rog frumos punctul b!!! Dau coroana!!

Anexe:

Ale20099: ex 16 punctul b

Răspunsuri la întrebare

Răspuns de PopaIonutAlin
0

 \frac{ \sqrt{2} -  \sqrt{3}  }{\sqrt{6} }  +  \frac{ \sqrt{3} -  \sqrt{4}   }{ \sqrt{12} }  +   \frac{ \sqrt{4} -  \sqrt{5}  }{ \sqrt{20} }  +  \frac{ \sqrt{5} -  \sqrt{6}  }{ \sqrt{30} }  +  \frac{ \sqrt{6} -  \sqrt{7}  }{ \sqrt{42} }  +  \frac{ \sqrt{7} -  \sqrt{8}  }{ \sqrt{56} }  \\  =  \frac{ \sqrt{2} }{ \sqrt{6} }  -  \frac{ \sqrt{3} }{ \sqrt{6} }  +  \frac{ \sqrt{3} }{ \sqrt{12} }  -   \frac{ \sqrt{4} }{ \sqrt{12} }  +  \frac{ \sqrt{4} }{ \sqrt{20} }  -  \frac{ \sqrt{5} }{ \sqrt{20} }  +  \frac{ \sqrt{5} }{ \sqrt{30} }  -  \frac{ \sqrt{6} }{ \sqrt{30} }  +  \frac{ \sqrt{6} }{ \sqrt{42} }  -  \frac{ \sqrt{7} }{ \sqrt{42} }  +  \frac{ \sqrt{7} }{ \sqrt{56} }  -  \frac{ \sqrt{8} }{ \sqrt{56} }  \\  =  \frac{ \sqrt{2} }{ \sqrt{2} \times  \sqrt{3}  }  -  \frac{ \sqrt{3} }{ \sqrt{2} \times  \sqrt{3}  }  +  \frac{ \sqrt{3} }{ \sqrt{3} \times  \sqrt{4}  }  -  \frac{ \sqrt{4} }{ \sqrt{3} \times  \sqrt{4}  }  +  \frac{ \sqrt{4} }{ \sqrt{4} \times  \sqrt{5}  }  -  \frac{ \sqrt{5} }{ \sqrt{4} \times  \sqrt{5}  }  +  \frac{ \sqrt{5} }{ \sqrt{5} \times  \sqrt{6}  }  -   \frac{ \sqrt{6} }{ \sqrt{5} \times  \sqrt{6}  }  +  \frac{ \sqrt{6} }{ \sqrt{6} \times  \sqrt{7}  }  -  \frac{ \sqrt{7} }{ \sqrt{6} \times  \sqrt{7}  }  +  \frac{ \sqrt{7} }{ \sqrt{7} \times  \sqrt{8}  }  -  \frac{ \sqrt{8} }{ \sqrt{7} \times  \sqrt{8}  }  \\  =  \frac{1}{ \sqrt{3} }  -  \frac{1}{ \sqrt{2}  }  +  \frac{1}{ \sqrt{4} }  -  \frac{1}{ \sqrt{3} }  +  \frac{1}{ \sqrt{5} }  -  \frac{1}{ \sqrt{4} }  +  \frac{1}{ \sqrt{6} }  -  \frac{1}{ \sqrt{5} }  +  \frac{1}{ \sqrt{7} }  -  \frac{1}{ \sqrt{6} }  +  \frac{1}{ \sqrt{8} }  -  \frac{1}{ \sqrt{7} }  \\  =  -\frac{1}{ \sqrt{2} }  +  \frac{1}{ \sqrt{8} }    \\  =  -\frac{1}{ \sqrt{2} }  +  \frac{1}{2 \sqrt{2} }  \\  =  -\frac{ \sqrt{2} }{2}  +  \frac{2 \sqrt{2} }{8}  =  -\frac{4 \sqrt{2} }{8}  +  \frac{ 2\sqrt{2} }{8}  =  -\frac{2 \sqrt{2} }{8}  =  -\frac{\sqrt{2} }{4}

Alte întrebări interesante