Question

Vă rog frumos puteți să mă ajutați dacă nu deranjez! Vă mulțumesc. ​

Answer 1

a) $2:(\frac{2}{3} )^2+\frac{11}{5} :\frac{11}{10} =$

$2:\frac{4}{9}+\frac{11}{5} *\frac{10}{11}=$

$2*\frac{9}{4}+\frac{2}{1}$$=$

$\frac{9}{2} +2=$

$\frac{9+4}{2} =\frac{13}{2}$

b) Aici n am inteles exact ce scrie la ultimul asa ca am presupus ca e cu minus

$(3-\frac{1}{3})^2+(2-\frac{1}{2} )^2-(1-\frac{1}{2} )^2=$

$(\frac{9-1}{3} )^2+(\frac{4-1}{2} )^2-(\frac{2-1}{2} )^2=$

$(\frac{8}{3} )^2+(\frac{3}{2} )^2-(\frac{1}{2} )^2=$

$\frac{64}{9} +\frac{9}{4} -\frac{1}{4} =$

$\frac{64}{9} -\frac{8}{4} =$$\frac{256}{36}+ \frac{72}{36}=\frac{328}{36} =\frac{82}{9}$