Question

va rog frumos❤ te rogggggg​

Answer 1

$\it\ a)\ \longrightarrow\ 3)\\ \\ b)\ \longrightarrow\ 4)\\ \\ c)\ \longrightarrow\ 1)\\ \\ d)\ \longrightarrow\ 2)$

$\it a)\ x^2:(3^2)^2=2^2 \Rightarrow x^2:9^2=2^2 \Rightarrow x^2=9^2\cdot2^2 \Rightarrow x=9\cdot2=18\\ \\ b)\ 196:x^2=7^4:7^2 \Rightarrow 14^2:x^2=7^2 \Rightarrow 14:x=7 \Rightarrow x=2\\ \\ c)\ 111_{(x)}=73_{(10)} \Rightarrow x^2+x+1=73|_{-1} \Rightarrow x(x+1)=72=8\cdot9 \Rightarrow x=8\\ \\ d)\ 324:5^x=(2\cdot3^2)^2 \Rightarrow 18^2:5^x=18^2 \Rightarrow 5^x=1 \Rightarrow x=0$

Answer 2

Răspuns:

a. = 3.

b. = 4.

c. aici chiar nush

d. = 2.

Explicație pas cu pas:

a.

x^2 : (3^2)^2 = 2^2

x^2 : 3^4 = 4

x^2 / 3^4 = 4

x^2 / 81 = 4

x^2 = 324

x = 18

b.

196 : x^2 = 7^4 : 7^2

196 / x^2 = 7^2

196 / x^2 = 49

196 = 49x^2

49x^2 = 196

x^2 = 4

x = 2

d.

324 / 5^x = (2x9)^2

324 / 5^x = 18^2

324 / 5^x = 324

324 = 324 x 5^x

324 x 5^x = 324

5^x = 1

5^x = 5^0

x = 0

Sper ca te am ajutat , o coroană daca se poate ;))