Question

Va rog....help ex 23

Answer 1

Răspuns:

a$a^{2} = 12$

Explicație pas cu pas:

a = ·$a = \sqrt{5-2\sqrt{6} }  + \sqrt{5+2\sqrt{6} } =\\ \sqrt{\sqrt{3} ^{2} -2\sqrt{3} \sqrt{2} + \sqrt{2} ^{2}  } +\sqrt{\sqrt{3} ^{2} +2\sqrt{3} \sqrt{2} + \sqrt{2} ^{2}  }=\\ \sqrt{(\sqrt{3} -\sqrt{2} )^{2} } + \sqrt{(\sqrt{3}+\sqrt{2} )^{2} } =\\ \sqrt{3} -\sqrt{2} +\sqrt{3} +\sqrt{2} =\\ 2\sqrt{3} \\a^{2} =(2\sqrt{3}) ^{2} =12$