Question

Va rog la matematică daca ma ajutati va rog frumos sa rezolvati pe foaie .

Answer 1

Sper ca te-am ajutat!

Answer 2

a)

$\frac{\sqrt{102,01}+x}{2x}=\frac{7,1}{14}$

$\frac{10,1+x}{2x}=\frac{7,1}{14}$

$=>14(10,1+x)=2x*7,1$

$141,4+14x=14,2x$

$0,2x=141,4$

$x=141,4:0,2$

$x=1414:2$

$x=707$


b)

$\frac{(\sqrt{2})^{4}*2^{-6}}{(\frac{1}{2})^{2}*2^{-2}}=x*(\frac{1}{\sqrt{2}})^{3}$

$\frac{4*\frac{1}{2^{6}}}{\frac{1}{2^{2}}*(\frac{1}{2})^{2}}=x*(\frac{1}{\sqrt{2}})^{3}$

$\frac{\frac{1}{2^{4}}}{\frac{1}{2^{4}}}=x*\frac{1}{2\sqrt{2}}$

$\frac{1}{2^{4}}*\frac{2^{4}}{1}=x*\frac{1}{2\sqrt{2}}$

$1=x*\frac{1}{2\sqrt{2}}$

$x=1*\frac{2\sqrt{2}}{1}$

$x=2\sqrt{2}$