Question

Va rog macar la cateva​

Answer 1

denumire = 1-butena

formula molec. = C4H8

formula procentuala:

M.C4H8 = 4x12+8x1 = 56 g/mol

56g alchena ....... 4x12g C ...... 8x1g H

100% ..................... a% C ............ b% H

                         = 85,71% C    14,29% H

omologii:

inferior = CH2=CH-CH3, propena

superior = CH2=CH-CH2-CH2-CH3, 1-pentena

izomerii:

de pozitie

CH2=CH-CH2-CH3, 1-butena

CH3-CH=CH-CH3, 2-butena

de catena

CH2=C-CH3 , 2-metilpropena

         CH3

geometrici

CH3 -     -CH3

      C=C

    H-     -H      , cis-2-butena

  H-      -CH3

      C=C

CH3-     -H      , trans-2-butena