Question

Va rog mult ajutati-ma nu stiu cum se face. Exercitiul de pe albastru. Multumesc.

Answer 1

MCH4 = 12+4=16g/mol
1mol=16g
1kmol=16kg=16000g

MCO2 = 12+16×2=44 g/mol
1mol=44g
1kmol=44kg=44000g

MC6H6= 6×12 + 6×1=78g/mol
1mol=78g
1kmol=78kg=78000g

Answer 2

CH4=A carbon+4*A hidrogen= 12+4*1=16g/mol
1mol CH4=16g/metan
1mol CH4=16*10³g metan=16000g=16kgCH4
Co2_=A carbon +2*A oxigen=12+2*16=44g/mol
1mol Co2=44g dioxidde carbon
1kmol Co2=44*10 la a 3 g dioxid de carbon=44000g=44kg Co2
C6H6=6*Acarbon+6*A hidrogen=12*6+6*1=78 g/mol
1mol C6H6=78G benzen
1kmol C6H6=1000mol078*10la a 3 g benzen =78000g=78 kg C6H6