Question

va rog mult de tot!!​

Answer 1

Răspuns:

Explicație pas cu pas:

E(x) = 3(x-5)²+2(x-4)(6-x)-6(5-x)+6 =>

E(x) = 3(x²-10x+25)+2(6x-x²-24+4x)-30+6x+6 =>

E(x) = 3x²-30x+75+2(-x²+10x-24)-24+6x =>

E(x) = 3x²-2x²-30x+20x+6x+75-48-24 =>

E(x) = x²-4x+3 = x²-3x-x+3 = x(x-3)-(x-3) =>

E(x) = (x-3)(x-1) , ∀ x ∈ R

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E(n) = 12-4n = (n-3)(n-1) =>

n²-4n+3 = 12-4n =>

n²= 9 => n₁,₂ = ±3