Question

va rog mult, E5 doar punctul a)

Answer 1

$|2x+3|-4*|2-(2x+5)|=-27 \\ \\ |2(x+ \frac{3}{2})|-4*|2-2x-5|=-27 \\ \\ 2*|x+ \frac{3}{2} | -4*|-3-2x|=-27 \\ \\ 2*|x + \frac{3}{2} |-4*|-2x-3|=-27 \\ \\ 2*|x+ \frac{3}{2} |-4*|-2(x+ \frac{3}{2} )|=-27 \\ \\ 2*|x+ \frac{3}{2}|-4*2*|x+ \frac{3}{2}|=-27 \\ \\ (1-4)*2*|x+ \frac{3}{2} |=-27 \\ \\ -3*2*|x+ \frac{3}{2}|=-27 \\ \\ -6*|x+ \frac{3}{2}|=-27 \\ \\ |x+ \frac{3}{2}|= \frac{9}{2} \\ \\ x_{1} + \frac{3}{2} = \frac{9}{2} \\ x_1=3 \\ \\ x_2 + \frac{3}{2} = - \frac{9}{2} \\ x_2=-6$
$x_2=-6, x_1=3$