Question

Vă rog răspuns detaliat, nu direct !

Answer 1

$f'(x)=\left(e^x+\dfrac{x-1}{x}\right)'=(e^x)'+\left(\dfrac{x-1}{x}\right)'= \\ =e^x +\dfrac{(x-1)'\cdot x-x'\cdot (x-1)}{x^2}=e^x+\dfrac{x-x+1}{x^2}=e^x+\dfrac{1}{x^2}$