Question

va rog repede dau coroană

Answer 1

a) Aplicam teorema lui Pitagora in ΔABC dreptunghic in A: BC²=AB²+AC²⇒BC=10

A=AB*AC/2=4,8

b)Aplicam teorema lui Pitagora in ΔABC dreptunghic in A:BC²=AB²+AC²⇒

AC=15

A=AB*AC/2=150

c)A=AB*AC/2⇔864=36*AC/2⇒AC=46

Aplicam teorema lui Pitagora in ΔABC dreptunghic in A:BC²=AB²+AC²⇒

BC=2√853

d)A=AB*AC/2=BC*AD/2⇒AD=1,44 m