Question

Vă rog repede pe 13 şi 14

Answer 1

13) a)
81:e=3
e=81:3
e=27

d=e*4
d=27*4
d=108

c=d+30
c=108+30
c=138

b=c:3
b=138:3
b=46

a=17+b
a=17+46
a=63

b)
e*30=180
e=180:30=6

d=162:e=162:6=27

c=d+17= 27+17=44

b=c*2=44*2=88

a=154-b=154-88=66

c)
e:9=18
e=18*9=162

d=e:6=162:6=27

c=d-21=27-21=6

b=c*5=6*5=30

a*b=300
a*30=300
a=10

d) nu se vede tot... Scrie in comentarii ce scrie despre "e" și voi edita raspunsul

14)
(4+a)(6-b)=12
1*12=12
2*6=12
3*4=12
4*3=12
6*2=12
12*1=12

4+a=1
a=-3

4+a=2
a=-2

4+a=3
a=-1

4+a=4
a=0

4+a=6
a=2

4+a=12
a=8

6-b=12
b=-6

6-b=6
b=0

6-b=4
b=2

6-b=3
b=3

6-b=2
b=4

6-b=1
b=5

Perechile de nr. (a, b) naturale sunt:
(4,3)
(2,4)
(8,5)



(16-a)(b+3)=15
1*15=15
3*5=15
5*3=15
15*1=15

16-a=1
a=17

16-a=3
a=13

16-a=5
a=11

16-a=15
a=1

b+3=15
b=12

b+3=5
b=2

b+3=3
b=0

b+3=1
b=-2

Perechile de nr. (a, b) naturale sunt:
(17,12)
(13,2)
(11,0)

(3+a)(b-5)=18
1*18
2*9
3*6
6*3
9*2
18*1

3+a=1
a=-2

3+a=2
a=-1

3+a=3
a=0

3+a=6
a=3

3+a=9
a=6

3+a=18
a=15

b-5=18
b=23

b-5=9
b=14

b-5=6
b=11

b-5=3
b=8

b-5=2
b=7

b-5=1
b=6

Perechile de nr. (a, b) naturale sunt:
(0,11)
(3,8)
(6,7)
(15,6)