Question

Va rog!!!!!!!!!
Reprezinta formula chimica pentru compusii cu urmatoarele compoziti procentoale:
c)27,38%Na;1,19%H'14,28%C;57,14%O
d)35%N;5%H;60%O

Answer 1

c)27,38%= 27,38g Na
1,19%=1,19g H
14,28%= 14,28g C
57,14%=17,14g O
Impartim fiecare masa la masa atomica a elementului respectiv:
27,38/ 23= 1,19 atomi-gram de Na
1,19/ 1=1,19atomi-gram H
14,28/ 12= 1,19atomi-gram C
57,14/ 16=3,57atomi-gram O
Impartim la cel mai mic:
1,19/1,19=1atom Na
1,19/1,19=1atom H
1,19/1,19=1 atom C
3,57/1,19= 3atomi O
Deci, formula chimica va fi:
Na1H1c1O3⇒NaHCO3=carbonat acid de sodiu

d) 35/14=2,5 atomi-gram N
     5/1=5 atomi-gram H
     60/16=3,75 atomi-gram O
    2,5/2,5= 1atom N
     5/2,5= 2 atomi H
     3,75/2,5=1,5 atomiO, aproximativ egal cu 2 atomiO
Formula chimica: H2NO2= acid azotos